Proposition: 1.02: Constructing a Segment Equal to an Arbitrary Segment
(Proposition 2 from Book 1 of Euclid's “Elements”)
To place a straight line equal to a given straight line at a given point (as an extremity).
* Let $A$ be the given point, and $BC$ the given straight line.
* So it is required to place a straight line at point $A$ equal to the given straight line $BC$.
Modern Formulation
Given an arbitrary point \(A\) and an arbitrary segment \(\overline{BC}\), it is possible to construct a segment \(\overline{AF}\) such that its length is equal to the length of \(\overline{BC}\).
Table of Contents
Proofs: 1
Mentioned in:
Proofs: 1
Sections: 2
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References
Adapted from CC BYSA 3.0 Sources:
 Callahan, Daniel: "Euclid’s 'Elements' Redux" 2014
Adapted from (Public Domain)
 Casey, John: "The First Six Books of the Elements of Euclid"
Adapted from (subject to copyright, with kind permission)
 Fitzpatrick, Richard: Euclid's "Elements of Geometry"