To cut off a segment, accepting an angle equal to a given rectilinear angle, from a given circle. * Let $ABC$ be the given circle, and $D$ the given rectilinear angle. * So it is required to cut off a segment, accepting an angle equal to the given rectilinear angle $D$, from the given circle $ABC$.
It is possible to construct segment of a circle, such that its inscribed angle ($\angle{CAB}$) is equal to a given rectilinear angle ($\angle D$) and its vertex ($A$) is located on this segment.
Proofs: 1
Sections: 1