In a circle, a diameter (is) the greatest (straight line), and for the others, a (straight line) nearer to the center is always greater than one further away. * Let $ABCD$ be a circle, and let $AD$ be its diameter, and $E$ (its) center. * And let $BC$ be nearer to the diameter $AD$,1 and $FG$ further away. * I say that $AD$ is the greatest (straight line), and $BC$ (is) greater than $FG$.
The longest chord in a circle is its diameter $\beta$. All chords in a circle have lengths $\gamma$ with $0 < \gamma \le \beta$. The chords are the longer the nearer they are to the center.
Proofs: 1
Proofs: 1