If there are any number of magnitudes whatsoever (which are) proportional then as one of the leading (magnitudes is) to one of the following, so will all of the leading (magnitudes) be to all of the following. * Let there be any number of magnitudes whatsoever, $A$, $B$, $C$, $D$, $E$, $F$, (which are) proportional, (so that) as $A$ (is) to $B$, so $C$ (is) to $D$, and $E$ to $F$. * I say that as $A$ is to $B$, so $A$, $C$, $E$ (are) to $B$, $D$, $F$.
In modern notation, this proposition reads that if \[\frac\alpha{\alpha'}=\frac\beta{\beta'}=\frac\gamma{\gamma'}=\ldots.\] then \[\frac\alpha{\alpha'}=\frac{\alpha+\beta+\gamma+\cdots}{\alpha'+\beta'+\gamma'+\cdots},\]
for all positive real numbers.
Proofs: 1
Proofs: 1 2 3 4 5 6 7 8 9 10
Sections: 11
