In equiangular triangles the sides about the equal angles are proportional, and those (sides) subtending equal angles correspond. * Let $ABC$ and $DCE$ be equiangular triangles, having angle $ABC$ equal to $DCE$, and (angle) $BAC$ to $CDE$, and, further, (angle) $ACB$ to $CED$. * I say that in triangles $ABC$ and $DCE$ the sides about the equal angles are proportional, and those (sides) subtending equal angles correspond.
Equiangular triangles are similar.
Proofs: 1
Definitions: 1
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Propositions: 18