There exists one number in mean proportion to two similar plane numbers. And (one) plane (number) has to the (other) plane (number) a squared^{1} ratio with respect to (that) a corresponding side (of the former has) to a corresponding side (of the latter). * Let $A$ and $B$ be two similar plane numbers. * And let the numbers $C$, $D$ be the sides of $A$, and $E$, $F$ (the sides) of $B$. * And since similar numbers are those having proportional sides [Def. 7.21] , thus as $C$ is to $D$, so $E$ (is) to $F$. * Therefore, I say that there exists one number in mean proportion to $A$ and $B$, and that $A$ has to $B$ a squared ratio with respect to that $C$ (has) to $E$, or $D$ to $F$ - that is to say, with respect to (that) a corresponding side (has) to a corresponding [side].
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Proofs: 1
Literally, "doubled" (translator's note) ↩