If a square (number) measures a(nother) square (number) then the side (of the former) will also measure the side (of the latter). And if the side (of a square number) measures the side (of another square number) then the (former) square (number) will also measure the (latter) square (number) . * Let $A$ and $B$ be square numbers, and let $C$ and $D$ be their sides (respectively). * And let $A$ measure $B$. * I say that $C$ also measures $D$. * So, again, let $C$ measure $D$. * I say that $A$ also measures $B$.
(not yet contributed)
Proofs: 1
Proofs: 1