If any multitude whatsoever of numbers is in continued proportion, (starting) from a unit, and the (number) after the unit is prime, then the greatest (number) will be measured by no [other] (numbers) except (numbers) existing among the proportional numbers. * Let any multitude whatsoever of numbers, $A$, $B$, $C$, $D$, be in continued proportion, (starting) from a unit. * And let the (number) after the unit, $A$, be prime. * I say that the greatest of them, $D$, will be measured by no other (numbers) except $A$, $B$, $C$.
(not yet contributed)
Proofs: 1