The square on the square root of (the sum of) two medial (areas) applied to a rational (straight line) produces as breadth a sixth binomial (straight line).1 * Let $AB$ be the square root of (the sum of) two medial (areas), having been divided at $C$. * And let $DE$ be a rational (straight line). * And let the (parallelogram) $DF$, equal to the (square) on $AB$, have been applied to $DE$, producing $DG$ as breadth. * I say that $DG$ is a sixth binomial (straight line).
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Proofs: 1
Proofs: 1
In other words, the square of the square root of two medials is a sixth binomial. See [Prop. 10.59] (translator's note). ↩
