If the side of a hexagon and of a decagon inscribed in the same circle are added together then the whole straight line has been cut in extreme and mean ratio (at the junction point), and its greater piece is the side of the hexagon. * Let $ABC$ be a circle. * And of the figures inscribed in circle $ABC$, let $BC$ be the side of a decagon, and $CD$ (the side) of a hexagon. * And let them be (laid down) straight-on (to one another). * I say that the whole straight line $BD$ has been cut in extreme and mean ratio (at $C$), and that $CD$ is its greater piece.
If the circle is of unit radius then the side of the hexagon is 1, whereas the side of the decagon is \[\frac {\sqrt{5}-1}2.\]
Proofs: 1