Proposition: 1.35: Parallelograms On the Same Base and On the Same Parallels
Euclid's Formulation
Parallelograms which are on the same base and between the same parallels are equal^{1} to one another.
 Let $ABCD$ and $EBCF$ be parallelograms on the same base $BC$, and between the same parallels $AF$ and $BC$.
 I say that $ABCD$ is equal to parallelogram $EBCF$.
Modern Formulation
Parallelograms on the same base (\(\overline{BC}\)) and between the same parallels (\(\overline{AF}\), \(\overline{BC}\)) are equal in area.
Table of Contents
Proofs: 1
Mentioned in:
Proofs: 1 2 3
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References
Adapted from CC BYSA 3.0 Sources:
 Callahan, Daniel: "Euclidâ€™s 'Elements' Redux" 2014
Adapted from (Public Domain)
 Casey, John: "The First Six Books of the Elements of Euclid"
Adapted from (subject to copyright, with kind permission)
 Fitzpatrick, Richard: Euclid's "Elements of Geometry"
Footnotes