Proof: By Euclid
(related to Proposition: 7.28: Numbers are Co-prime iff Sum is Co-prime to Both)
- "$\Rightarrow$"
- Let the two numbers, $AB$ and $BC$, (which are) prime to one another, be laid out.
- Assume, $CA$ and $AB$ are not prime to one another.
- Then some number will measure $CA$ and $AB$.
- Let it (so) measure (them), and let it be $D$.
- Therefore, since $D$ measures $CA$ and $AB$, it will thus also measure the remainder $BC$.
- And it also measures $BA$.
- Thus, $D$ measures $AB$ and $BC$, which are prime to one another.
- The very thing is impossible.
- Thus, some number cannot measure (both) the numbers $CA$ and $AB$.
- Thus, $CA$ and $AB$ are prime to one another.
- So, for the same (reasons), $AC$ and $CB$ are also prime to one another.
- Thus, $CA$ is prime to each of $AB$ and $BC$.
- "$\Leftarrow$"
- So, again, let $CA$ and $AB$ be prime to one another.
- For if $AB$ and $BC$ are not prime to one another then some number will measure $AB$ and $BC$.
- Let it (so) measure (them), and let it be $D$.
- And since $D$ measures each of $AB$ and $BC$, it will thus also measure the whole of $CA$.
- And it also measures $AB$.
- Thus, $D$ measures $CA$ and $AB$, which are prime to one another.
- The very thing is impossible.
- Thus, some number cannot measure (both) the numbers $AB$ and $BC$.
- Thus, $AB$ and $BC$ are prime to one another.
- (Which is) the very thing it was required to show.
∎
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References
Adapted from (subject to copyright, with kind permission)
- Fitzpatrick, Richard: Euclid's "Elements of Geometry"