Proposition: Prop. 10.042: Binomial Straight Line is Divisible into Terms Uniquely

Euclid's Formulation

A binomial (straight line) can be divided into its (component) terms at one point only.

fig042e

Modern Formulation

In other words, \[\alpha + \sqrt{\beta} = \gamma + \sqrt{\delta}\] has only one solution: i.e., \[\gamma=\alpha\quad\text{ and }\quad\delta=\beta,\] where \(\alpha,\beta,\gamma,\delta\) denote positive rational numbers. Likewise, \[\sqrt{\alpha} + \sqrt{\beta} =\sqrt{\gamma}+\sqrt{\delta}\] has only one solution: i.e., \[\gamma=\alpha\quad\text{ and }\quad\delta=\beta,\] or, equivalently, \[\gamma=\beta\quad\text{ and }\quad\delta=\alpha.\]

Notes

This proposition corresponds to [Prop. 10.79], with plus signs instead of minus signs.

Proofs: 1

Proofs: 1 2
Propositions: 3


Thank you to the contributors under CC BY-SA 4.0!

Github:
bookofproofs
non-Github:
@Fitzpatrick


References

Adapted from (subject to copyright, with kind permission)

  1. Fitzpatrick, Richard: Euclid's "Elements of Geometry"

Adapted from CC BY-SA 3.0 Sources:

  1. Prime.mover and others: "Pr∞fWiki", https://proofwiki.org/wiki/Main_Page, 2016