(related to Proposition: Multiplication Of Rational Numbers Is Commutative)
Let \(x,y\in\mathbb Q\) be rational numbers, which by definition means that each rational number is an equivalence class of ordered pairs of integers represented by some integers \(a,b,c,d\in\mathbb Z\), with \(b\neq 0,d\neq 0\)^{1}:
\[\begin{array}{cc}x:=\frac ab,&y:=\frac cd.\end{array}\]
In order to show the law \[x\cdot y=y\cdot x\] we use the following mathematical definitions and concepts: * definition of rational numbers. * definition of multiplying rational numbers, and * commutativity law for multiplying integers. \[\begin{array}{rcll} x\cdot y&=&\frac ab\cdot \frac cd&\text{by definition of rational numbers}\\ &=&\frac {ac}{bd}& \text{by definition of multiplying rational numbers}\\ &=&\frac {ca}{db}& \text{by commutativity of multiplying integers}\\ &=&\frac cd\cdot \frac ab& \text{by definition of multiplying rational numbers}\\ &=&y\cdot x&\text{by definition of rational numbers} \end{array}\]
Note that the symbol "\(0\)" denotes the zero defined for integers, and not the zero defined for rational numbers. ↩