Proposition: Unique Solvability of $ax=b$
The equation of \(ax=b\) is uniquely solvable by \(x=ba^{-1}\) for all \(a,b\in\mathbb R\), \(a \neq 0\).
Table of Contents
Proofs: 1
Mentioned in:
Proofs: 1 2
Thank you to the contributors under CC BY-SA 4.0! 
- Github:
-
