Proposition: Subgroups of Finite Cyclic Groups

Let \((G,\ast)\) be a finite cyclic group, i.e. \(|G|=n < \infty\) and let \(d\mid n\) be a divisor of \(n\). Then there exists exactly one subgroup \(H\subseteq G\) with \(|H|=d\).

Proofs: 1


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References

Bibliography

  1. Modler, Florian; Kreh, Martin: "Tutorium Algebra", Springer Spektrum, 2013