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Proposition: Subgroups of Finite Cyclic Groups
Let \((G,\ast)\) be a finite cyclic group, i.e. \(G=n < \infty\) and let \(d\mid n\) be a divisor of \(n\). Then there exists exactly one subgroup \(H\subseteq G\) with \(H=d\).
Table of Contents
Proofs: 1
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References
Bibliography
 Modler, Florian; Kreh, Martin: "Tutorium Algebra", Springer Spektrum, 2013