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Proposition: Derivative of the Inverse Tangent

The derivative of the inverse tangent $\arctan(x),$ $-1 < x < 1,$ is given by $$\arctan'(x)=\frac1{1+x^2}.$$

Table of Contents

Proofs: 1

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References

Bibliography

  1. Forster Otto: "Analysis 1, Differential- und Integralrechnung einer Veränderlichen", Vieweg Studium, 1983