Solution

(related to Problem: Mrs. Timpkin's Age)

The age of the younger at marriage is always the same as the number of years that expire before the elder becomes twice her age if he was three times as old at marriage. In our case it was eighteen years afterwards; therefore Mrs. Timpkins was eighteen years of age on the wedding-day, and her husband fifty-four.


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References

Project Gutenberg

  1. Dudeney, H. E.: "Amusements in Mathematics", The Authors' Club, 1917

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