(related to Problem: The Rookery)
The answer involves the little point that in the final position the numbered rooks must be in numerical order in the direction contrary to that in which they appear in the original diagram, otherwise, it cannot be solved. Play the rooks in the following order of their numbers. As there is never more than one square to which a rook can move (except on the final move), the notation is obvious — $5, 6, 7, 5, 6,$ $4, 3, 6, 4, 7, 5,$ $4, 7, 3, 6, 7, 3,$ $5, 4, 3, 1, 8,$ $3, 4, 5, 6,$ $7, 1, 8, 2, 1,$ and rook takes bishop, checkmate. These are the fewest possible moves — thirty-two. The Black king's moves are all forced, and need not be given.
This eBook is for the use of anyone anywhere in the United States and most other parts of the world at no cost and with almost no restrictions whatsoever. You may copy it, give it away or re-use it under the terms of the Project Gutenberg License included with this edition or online at http://www.gutenberg.org. If you are not located in the United States, you'll have to check the laws of the country where you are located before using this ebook.
