(related to Problem: King Arthur's Knights)

On the second evening King Arthur arranged the knights and himself in the following order around the table: $A, F, B, D, G, E, C.$ On the third evening they sat thus, $A, E, B, G, C, F, D.$ He thus had $B$ next but one to him on both occasions (the nearest possible), and G was the third from him at both sittings (the furthest position possible). No other way of sitting the knights would have been so satisfactory.

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Project Gutenberg

  1. Dudeney, H. E.: "Amusements in Mathematics", The Authors' Club, 1917

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