(related to Problem: Painting The Die)
The $1$ can be marked on any one of six different sides. For every side occupied by $1$ we have a selection of four sides for the $2.$ For every situation of the $2$ we have two places for the $3.$ (The $6, 5,$ and $4$ need not be considered, as their positions are determined by the $1, 2,$ and $3.$) Therefore $6, 4,$ and $2$ multiplied together make $48$ different ways — the correct answer.
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