Proposition: Prop. 10.088: Construction of Fourth Apotome
(Proposition 88 from Book 10 of Euclid's “Elements”)
To find a fourth apotome.
- Let the rational (straight line) $A$, and $BG$ (which is) commensurable in length with $A$, be laid down.
- Thus, $BG$ is also a rational (straight line).
- And let the two numbers $DF$ and $FE$ be laid down such that the whole, $DE$, does not have to each of $DF$ and $EF$ the ratio which (some) square number (has) to (some) square number.
- And let it have been contrived that as $DE$ (is) to $EF$, so the square on $BG$ (is) to the (square) on $GC$ [Prop. 10.6 corr.] .
- The (square) on $BG$ is thus commensurable with the (square) on on $GC$ [Prop. 10.6].
- And the (square) on $BG$ (is) rational.
- Thus, the (square) on $GC$ (is) also rational.
- Thus, $GC$ (is) a rational (straight line).
- And since $DE$ does not have to $EF$ the ratio which (some) square number (has) to (some) square number, the (square) on $BG$ thus does not have to the (square) on $GC$ the ratio which (some) square number (has) to (some) square number either.
- Thus, $BG$ is incommensurable in length with $GC$ [Prop. 10.9].
- And they are both rational (straight lines).
- Thus, $BG$ and $GC$ are rational (straight lines which are) commensurable in square only.
- Thus, $BC$ is an apotome [Prop. 10.73].
- So, I say that (it is) also a fourth (apotome) ]
Modern Formulation
This proposition proves that the fourth apotome has length
\[\alpha-\frac \alpha{\sqrt{1+\beta}},\]
where \(\alpha,\beta\) denote positive rational numbers.
Notes
See also [Prop. 10.51].
Table of Contents
Proofs: 1
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Propositions: 1
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References
Adapted from (subject to copyright, with kind permission)
- Fitzpatrick, Richard: Euclid's "Elements of Geometry"
Adapted from CC BY-SA 3.0 Sources:
- Prime.mover and others: "Pr∞fWiki", https://proofwiki.org/wiki/Main_Page, 2016