Proof: By Euclid
(related to Proposition: Prop. 12.08: Volumes of Similar Tetrahedra are in Cubed Ratio of Corresponding Sides)
- For let the parallelepiped solids $BGML$ and $EHQP$ have been completed.
- And since pyramid $ABCG$ is similar to pyramid $DEFH$, angle $ABC$ is thus equal to angle $DEF$, and $GBC$ to $HEF$, and $ABG$ to $DEH$.
- And as $AB$ is to $DE$, so $BC$ (is) to $EF$, and $BG$ to $EH$ [Def. 11.9] .
- And since as $AB$ is to $DE$, so $BC$ (is) to $EF$, and (so) the sides around equal angles are proportional, parallelogram $BM$ is thus similar to paralleleogram $EQ$.
- So, for the same (reasons), $BN$ is also similar to $ER$, and $BK$ to $EO$.
- Thus, the three (parallelograms) $MB$, $BK$, and $BN$ are similar to the three (parallelograms) $EQ$, $EO$, $ER$ (respectively).
- But, the three (parallelograms) $MB$, $BK$, and $BN$ are (both) equal and similar to the three opposite (parallelograms), and the three (parallelograms) $EQ$, $EO$, and $ER$ are (both) equal and similar to the three opposite (parallelograms) [Prop. 11.24].
- Thus, the solids $BGML$ and $EHQP$ are contained by equal numbers of similar (and similarly laid out) planes.
- Thus, solid $BGML$ is similar to solid $EHQP$ [Def. 11.9] .
- And similar parallelepiped solids are in the cubed ratio of corresponding sides [Prop. 11.33].
- Thus, solid $BGML$ has to solid $EHQP$ the cubed ratio that the corresponding side $BC$ (has) to the corresponding side $EF$.
- And as solid $BGML$ (is) to solid $EHQP$, so pyramid $ABCG$ (is) to pyramid $DEFH$, inasmuch as the pyramid is the sixth part of the solid, on account of the prism, being half of the parallelepipedal solid [Prop. 11.28], also being three times the pyramid [Prop. 12.7].
- Thus, pyramid $ABCG$ also has to pyramid $DEFH$ the cubed ratio that $BC$ (has) to $EF$.
- (Which is) the very thing it was required to show.
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References
Adapted from (subject to copyright, with kind permission)
- Fitzpatrick, Richard: Euclid's "Elements of Geometry"