(related to Problem: The Stop-Watch)
The time indicated on the watch was $5\frac{5}{11}$ min. past $9,$ when the second hand would be at $27\frac{3}{11}$ sec. The next time the hands would be similar distances apart would be $54\frac{6}{11}$ min. past $2,$ when the second hand would be at $32\frac{8}{11}$ sec. But you need only hold the watch (or our previous illustration of it) in front of a mirror, when you will see the second time reflected in it! Of course, when reflected, you will read XI as I, X as II, and so on.
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