(related to Problem: Square Money)

The answer is $1\frac 12$d. and $3$d. Added together they make $4\frac 12$d., and $1\frac 12$d. multiplied by $3$ is also $4\frac 12$d.

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Project Gutenberg

  1. Dudeney, H. E.: "Amusements in Mathematics", The Authors' Club, 1917

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