Solution

(related to Problem: The Parish Council Election)

The voter can vote for one candidate in $23$ ways, for two in $253$ ways, for three in $1,771,$ for four in $8,855,$ for five in $33,649,$ for six in $100,947,$ for seven in $245,157,$ for eight in $490,314,$ and for nine candidates in $817,190$ different ways. Add these together, and we get the total of $1,698,159$ ways of voting.


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References

Project Gutenberg

  1. Dudeney, H. E.: "Amusements in Mathematics", The Authors' Club, 1917

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