(related to Problem: The Queen's Tour)
The annexed diagram shows a second way of performing the Queen's Tour. If you break the line at the point $J$ and erase the shorter portion of that line, you will have the required path solution for any $J$ square. If you break the line at $I,$ you will have a non-re-entrant solution starting from any $I$ square. And if you break the line at $G,$ you will have a solution for any $G$ square. The Queen's Tour previously given may be similarly broken at three different places, but I seized the opportunity of exhibiting a second tour.
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