# Solution

(related to Problem: Card Magic Squares)

Arrange the cards as follows for the three new squares:— $$\begin{array}{ccc} 3&2&4\\ 4&3&2\\ 2&4&3\\ \\ 6&5&7\\ 7&6&5\\ 5&7&6\\ \\ 9&8&10\\ 10&9&8\\ 8&10&9\\ \end{array}$$

Three aces and one ten are not used. The summations of the four squares are thus: $9,$ $15,$ $18,$ and $27$ — all different, as required.

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### References

#### Project Gutenberg

1. Dudeney, H. E.: "Amusements in Mathematics", The Authors' Club, 1917

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