Proposition: Prop. 10.090: Construction of Sixth Apotome
(Proposition 90 from Book 10 of Euclid's “Elements”)
To find a sixth apotome.
 Let the rational (straight line) $A$, and the three numbers $E$, $BC$, and $CD$, not having to one another the ratio which (some) square number (has) to (some) square number, be laid down.
 Furthermore, let $CB$ also not have to $BD$ the ratio which (some) square number (has) to (some) square number.
 And let it have been contrived that as $E$ (is) to $BC$, so the (square) on $A$ (is) to the (square) on $FG$, and as $BC$ (is) to $CD$, so the (square) on $FG$ (is) to the (square) on $GH$ [Prop. 10.6 corr.] .
 Therefore, since as $E$ is to $BC$, so the (square) on $A$ (is) to the (square) on $FG$, the (square) on $A$ (is) thus commensurable with the (square) on on $FG$ [Prop. 10.6].
 And the (square) on $A$ (is) rational.
 Thus, the (square) on $FG$ (is) also rational.
 Thus, $FG$ is also a rational (straight line).
 And since $E$ does not have to $BC$ the ratio which (some) square number (has) to (some) square number, the (square) on $A$ thus does not have to the (square) on $FG$ the ratio which (some) square number (has) to (some) square number either.
 Thus, $A$ is incommensurable in length with $FG$ [Prop. 10.9].
 Again, since as $BC$ is to $CD$, so the (square) on $FG$ (is) to the (square) on $GH$, the (square) on $FG$ (is) thus commensurable with the (square) on on $GH$ [Prop. 10.6].
 And the (square) on $FG$ (is) rational.
 Thus, the (square) on $GH$ (is) also rational.
 Thus, $GH$ (is) also rational.
 And since $BC$ does not have to $CD$ the ratio which (some) square number (has) to (some) square number, the (square) on $FG$ thus does not have to the (square) on $GH$ the ratio which (some) square (number) has to (some) square (number) either.
 Thus, $FG$ is incommensurable in length with $GH$ [Prop. 10.9].
 And both are rational (straight lines).
 Thus, $FG$ and $GH$ are rational (straight lines which are) commensurable in square only.
 Thus, $FH$ is an apotome [Prop. 10.73].
 So, I say that (it is) also a sixth (apotome) .
Modern Formulation
This proposition proves that the sixth apotome has length
\[\sqrt{\alpha}\sqrt{\beta},\]
where \(\alpha,\beta\) denote positive rational numbers.
Notes
See also [Prop. 10.53].
Table of Contents
Proofs: 1
Mentioned in:
Propositions: 1
Thank you to the contributors under CC BYSA 4.0!
 Github:

 nonGithub:
 @Fitzpatrick
References
Adapted from (subject to copyright, with kind permission)
 Fitzpatrick, Richard: Euclid's "Elements of Geometry"
Adapted from CC BYSA 3.0 Sources:
 Prime.mover and others: "Pr∞fWiki", https://proofwiki.org/wiki/Main_Page, 2016