Axiom: Peano Axioms

Let \(N\) be a set fulfilling the following axioms:

  1. P1: \(N\) contains the element \(0\).
  2. P2: For each element \(n\in N\) there exists a unique element \(n^+\), the so-called successor of n1.
  3. P3: There is no element \(n\in N\) such that \(n^+=0\) (i.e. \(0\) is not a successor of any element of \(N\)).
  4. P4: If two elements \(n,~m\in N\) have the same successors \(n^+=m^+\) then they are the same \(n=m\).
  5. P5: If a subset \(A\subset N\) contains the element \(0\) and with each element \(n\) contained in it it also contains the successor \(n^+\), then \(A\) must be the set \(N\) (principle of induction).

Explanations: 1

  1. Definition: Set of Natural Numbers (Peano)

Branches: 1
Definitions: 2 3
Explanations: 4
Parts: 5 6
Proofs: 7 8 9 10
Propositions: 11 12


Thank you to the contributors under CC BY-SA 4.0!

Github:
bookofproofs


Footnotes


  1. In P2 we denote \(n\) the predecessor of \(n^+\).